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Exercise 23.4
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Joined: 27 Sep 2009, 22:10
Posts: 1
The solution for 23.4 (see http://camoo.freeshell.org/23.4.gif) states that:

^L * vR - vL * ^R = (^L + ^R) * (vR - vL)

- why so?

This holds only if ^R * vR - ^L * vL = 0 (or ^R * vR = 0, ^L * vL = 0)

- why should it be true?

02 Oct 2009, 14:06 Joined: 23 Aug 2010, 13:12
Posts: 33
Penrose says he is using the position, left ket or right ket, to distinguish the two particles -- not the "L" or "R" label, which can apparently be thought of as distinguishing different spatial versions of the wavefunction. If we remove the L and R, so the spatial parts are identical, we *might* imagine canceling the RR versus LL terms. However, the derivation is still not valid because Laura equates ^RvL with vL^R. Changing the order of the terms is not allowed -- it amounts to interchanging the particles' wavefunctions. Frankly, I dont see how Penrose's claim that the singlet state can be expressed as a product can possibly be true. Obviously, I dont get what he is trying to convey.

26 Sep 2010, 12:45 Joined: 13 Mar 2008, 14:06
Posts: 42
Location: Ithaca NY
What I was talking about in that solution is that the RH particle - that's R - is not both spin-up and spin-down at the same time. SImilarly the LH particle.

In other words,
^R> vR> = <^R|vR> = 0

The multiplication here is the inner product in a complex vector space. The inner product of ^R> and vR> is the complex conjugate of ^R> dotted with vR>, which is the same as <^R|vR>, or the amplitude of ^R>, given vR>.

For example, if the complex vector space has only 1 dimension, so it's only the complex numbers, the inner product of x and y is xbar times y. If it had 2 dimensions, the inner product (x1,x2)(y1,y2) = x1bar times y1 + x2bar times y2.

THe complex vector space inner product isn't commutative, that's right. inner product of x and y is the complex conjugate of the inner product of y and x.

Laura

13 Oct 2010, 16:38 Page 1 of 1 [ 3 posts ] 