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Archived: 07 Aug 2014, 10:01
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gshmelev
Joined: 27 Sep 2009, 22:10 Posts: 1
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 Exercise 23.4
The solution for 23.4 (see http://camoo.freeshell.org/23.4.gif) states that: ^L * vR - vL * ^R = (^L + ^R) * (vR - vL) - why so? This holds only if ^R * vR - ^L * vL = 0 (or ^R * vR = 0, ^L * vL = 0) - why should it be true?
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02 Oct 2009, 14:06 |
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Smith
Joined: 23 Aug 2010, 13:12 Posts: 33
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 Re: Exercise 23.4
Penrose says he is using the position, left ket or right ket, to distinguish the two particles -- not the "L" or "R" label, which can apparently be thought of as distinguishing different spatial versions of the wavefunction. If we remove the L and R, so the spatial parts are identical, we *might* imagine canceling the RR versus LL terms. However, the derivation is still not valid because Laura equates ^RvL with vL^R. Changing the order of the terms is not allowed -- it amounts to interchanging the particles' wavefunctions. Frankly, I dont see how Penrose's claim that the singlet state can be expressed as a product can possibly be true. Obviously, I dont get what he is trying to convey.
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26 Sep 2010, 12:45 |
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fallingup
Joined: 13 Mar 2008, 14:06 Posts: 42 Location: Ithaca NY
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 Re: Exercise 23.4
What I was talking about in that solution is that the RH particle - that's R - is not both spin-up and spin-down at the same time. SImilarly the LH particle.
In other words, ^R> vR> = <^R|vR> = 0
The multiplication here is the inner product in a complex vector space. The inner product of ^R> and vR> is the complex conjugate of ^R> dotted with vR>, which is the same as <^R|vR>, or the amplitude of ^R>, given vR>.
For example, if the complex vector space has only 1 dimension, so it's only the complex numbers, the inner product of x and y is xbar times y. If it had 2 dimensions, the inner product (x1,x2)(y1,y2) = x1bar times y1 + x2bar times y2.
THe complex vector space inner product isn't commutative, that's right. inner product of x and y is the complex conjugate of the inner product of y and x.
Laura
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13 Oct 2010, 16:38 |
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