[ 1 post ] 
 Exercise [06.06] 
Author Message

Joined: 12 Mar 2008, 10:57
Posts: 69
Location: India
Post Exercise [06.06]
y=x^n
We know if y=u_{1}v_{1} then dy=u_{1}dv_{1}+v_{1}du_{1}.
Put u_{1}=x and v_{1}=x^{n-1},then put v_{1}=xv_{2}wherev_{2}=x^{n-2},then put v_{2}=xv_{3}wherev_{3}=x^{n-3} and so on till v_{n-1}=xv_{n}where v_{n}=x^{n-n}=x^0=1
d(x^n)=d(xx...ntimes)=(x^{n-1} +x^{n-1} +... ntimes)dx=n(x^{n-1})dx


02 Apr 2008, 08:41
   [ 1 post ]