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 Exercise [05.06] 
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Joined: 25 Feb 2008, 13:32
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Location: Cape Town, South Africa
Post Exercise [05.06]
-1=e^{\pi  i}
\therefore \log _e(-1)=\text{$\pi $i}

w=e^z
\therefore \log _e(w)=z

\log _e(w)+\log _e(-1)=\log _e(-w)
\therefore \log _e(-w)=z+\text{$\pi $i}

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Our imagination is stretched to the utmost, not, as in fiction, to imagine things which are not really there, but just to comprehend those things which are there.


26 Mar 2008, 07:29
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Joined: 19 Mar 2008, 14:09
Posts: 36
Post Re: Exercise [6.5]
Shaun Culver wrote:
-1=e^{\pi  i}
\therefore \log _e(-1)=\text{$\pi $i}

w=e^z
\therefore \log _e(w)=z

\log _e(w)+\log _e(-1)=\log _e(-w)
\therefore \log _e(-w)=z+\text{$\pi $i}

Is that not exercise 5.6? ;)


26 Mar 2008, 12:04
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Joined: 25 Feb 2008, 13:32
Posts: 106
Location: Cape Town, South Africa
Post Re: Exercise [6.5]
My mistake. Thank you.

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Our imagination is stretched to the utmost, not, as in fiction, to imagine things which are not really there, but just to comprehend those things which are there.


26 Mar 2008, 12:17
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