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Exercise [13.05]
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Joined: 12 Mar 2008, 10:57
Posts: 69
Location: India
Exercise [13.05]
The set {1,-1,i,-i} is closed under multipilication.It contains the identity 1 and every element has an inverse.1 and -1 are inverses of themselves while i and -i are inverses of each other.The given set is a subset of the group of symmetries of the square. Hence,this set is a subgroup of .In fact,it is a cyclic group with i and -i as generators.
On the other hand the subset {1,-1,C,-C} is not a cyclic group.Closure can be easily verified.The identity 1 is in the set.Moreover,each element is its own inverse.Hence,the set is a subgroup of .
These two subgroups are the only two group structures of order 4.The former is isomorphic to while the latter is isomorphic to V,that is Klein-4 group.(In fact,it follows from the fundamental theorem of finitely generated abelian groups that V is isomorphic to x)
The other subset {1,-1} is a subgroup as it is isomorphic to .

25 Aug 2008, 07:38
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