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 Exercise [12.12] 
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Joined: 07 May 2009, 16:45
Posts: 62
Post Exercise [12.12]
Why? (A 1-form \boldsymbol \alpha which is a gradient \boldsymbol \alpha = d \Phi must satisfy d \boldsymbol \alpha = 0, by d^2=0)

\Phi is a 0-form, which qualifies as a p-form, so d \boldsymbol \alpha = d(d\Phi)) = d^2 \Phi = 0


01 Aug 2009, 01:53

Joined: 23 Aug 2010, 13:12
Posts: 33
Post Re: Exercise [12.12]
The result can be established directly. See PDF file


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24 Aug 2010, 00:10
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