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 Exercise [10.06] 
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Joined: 12 Mar 2008, 10:57
Posts: 69
Location: India
Post Exercise [10.06]
f(x,y)=x^3-y^3=(x-y)(x^2+xy+y^2)
=(x-y)\{{(x-y)}^2+3xy\}=X(X^2+3Y)=X^3+3XY=F(X,Y)


13 May 2008, 10:34
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