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Archived: 07 Aug 2014, 10:04
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robin
Joined: 26 Mar 2010, 04:39 Posts: 109
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 Exercise [21.15]
Here is exercise 21.15.
(Updated solution file on 14 August 2010)
Attachments:
File comment: Exercise 21.15
Exercise21.15.pdf [135.06 KiB]
Downloaded 146 times
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03 Aug 2010, 02:54 |
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robin
Joined: 26 Mar 2010, 04:39 Posts: 109
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 Re: Exercise [21.15]
There were some slight errors in my solution file which I have now corrected.
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14 Aug 2010, 02:09 |
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deant
Joined: 12 Jul 2010, 07:44 Posts: 154
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 Re: Exercise [21.15]
I solved it more-or-less similarly.
The essential differences were only that I used the results of Exercise [21.11] to first transform my integral, and that I used the fact that the area under a normal distribution is 1, rather than using the result of Exercise [12.10] (but that amounts to the same thing).
However, neither of us have used the results of Exercise [21.13] or [21.14] in our solutions, as the question asked us to do.
Does anyone have any idea how this might be solved using the results of Exercise [21.13] and [21.14]? (because I don't!)
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08 Sep 2012, 14:14 |
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